1 组均值 ± ½HSD · 两条不重叠 = 显著不同 Group Means ± ½HSD · Non-Overlapping = Significantly Different
HSD=—2 为什么不能裸做两两 t · 家族误差爆炸 Why Not Just Run Pairwise t · Family-Wise Error Explodes
红线:裸 t 的家族假阳性 1−(1−α)^m 随比较数 m 飙升;绿线:Tukey HSD 把它压平在 α=0.05。 Red: naive-t family-wise false positives 1−(1−α)^m climb with the number of comparisons m; green: Tukey HSD holds it flat at α=0.05.
3 动手算一遍 · 4 组显著后定位差异 Work It Out · Locating Differences After a Significant 4-Group ANOVA
背景:单因子 ANOVA 已显著。k=4 组,每组 n=5,MSW=6,组均值: Setup: one-way ANOVA already significant. k=4 groups, n=5 each, MSW=6, group means: x̄₁=20, x̄₂=23, x̄₃=27, x̄₄=30
HSD = q·√(MSW/n) = 4.05·√(6/5) = 4.05·1.095 = 4.44
|x̄₁−x̄₂| = 3 < 4.44 → ns · |x̄₁−x̄₃| = 7 > 4.44 → sig
|x̄₁−x̄₄| = 10 > 4.44 → sig · |x̄₂−x̄₃| = 4 < 4.44 → ns
|x̄₂−x̄₄| = 7 > 4.44 → sig · |x̄₃−x̄₄| = 3 < 4.44 → ns
结论:6 对里 3 对显著(1-3、1-4、2-4)。相邻组两两拉不开,但跨度大的能分开 —— 组呈现「重叠梯队」:{1,2}、{2,3}、{3,4} 各自内部不可区分,但 1 明显低于 3、4,2 明显低于 4。若当初用 6 次裸 t,家族假阳性率已是 1−0.95⁶ = 26.5%。 Conclusion: of 6 pairs, 3 are significant (1-3, 1-4, 2-4). Adjacent groups don't separate, but wide spans do — the groups form "overlapping tiers": {1,2}, {2,3}, {3,4} are internally indistinguishable, yet 1 is clearly below 3 and 4, and 2 below 4. Had you run 6 naive t-tests, the family-wise false-positive rate would already be 1−0.95⁶ = 26.5%.